14j^2-217j-112=0

Solution for 14j^2-217j-112=0 equation:

14j^2-217j-112=0

a = 14; b = -217; c = -112;
Δ = b2-4ac
Δ = -2172-4·14·(-112)
Δ = 53361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{53361}=231$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-217)-231}{2*14}=\frac{-14}{28}
=-1/2
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-217)+231}{2*14}=\frac{448}{28}
=16
$